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-=[ Science and Engineering]=-
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| Three brothers check into a hotel and rent one room. the Clerk tells them the room is $30 for the night, so each brother contributes $10 and the room is paid in advance. |
About an hour after check-in the clerk discovers that he charged the weekend rate of $30 instead of the weekday rate of $ 25. The Clerk gives the bellhop $ 5.00 to return to the brothers. On the way up to the room the bellhop pockets $ 2.00 and returns only $ 3.00 to the Brothers.
Now: Each Brother has paid $9.00 toward the room or $27.00 and the Bellhop kept $ 2.00 for a total of $ 29.00.
What happened to the extra $ 1.00 ??
Answer below ...
Well nothing really. There is no extra dollar. What we have in this puzzle is a break in the laws of Algebra or a better way to see what happened is to break the money into "Givers and Receivers"
First pass of the money:
Receiver == Givers
Hotel $30 = Brothers $10 +10 +10 (An equal equation!)
Second Pass of the money:
Receivers == Givers
Hotel $25 + Bhop $ 2 = Brothers $9 + 9 + 9 (Again all even at $27)
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